tolong bantu jawab yang bener jangan ngasal
Jawab:
segitiga siku
kesebangunan
ΔACB siku di C
CD tegak lurus AB
AC² = AD x AB
AC² = 12 x (12 +4)
AC² = 12 x 16
AC =√12 x √16
AC = 2√3 (4)
AC = 8√3
BC² = BD x BA
BC² = 4 x (4 +12)
BC² = 4 x 16
BC = √4 x √16
BC = 2 x 4
BC = 8
CD² = AD x DB
CD² = 12 x 4= 48
CD = √48 = √16 x √3
CD = 4√3